🏠 Home 📘 Track 2: Mathematics for Quantum ← M04: The Imaginary Unit M05: The Complex Plane M06: Polar Form →
M05 §1 · Complex Numbers ~14 min

The complex plane — every z as a 2D point

A complex number $z = a + bi$ isn't just a calculation result. It's a point on a plane — with a position, a distance from the origin, and a direction. Dragging that point is the fastest way to feel its geometry.

✦ Central Idea Every complex number $z = a + bi$ is a 2D point at coordinates $(a, b)$. Its distance from the origin — the modulus $|z| = \sqrt{a^2 + b^2}$ — is what quantum probabilities ultimately depend on.
complex plane real axis imaginary axis modulus argument Cartesian form
Section 1

You know what a complex number is. But do you know where it lives?

You've met $i$ — the square root of $-1$. You can write $z = 3 + 4i$ and follow the algebra. But here's what most textbooks skip: a complex number isn't just an algebraic expression. It's a location. It lives somewhere.

Real numbers live on a line — the number line you've used since childhood. Where does $3 + 4i$ live? It can't go on that line. $i$ points in a direction perpendicular to real numbers, which means complex numbers live in a plane — a flat 2D surface with two axes.

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Why this matters for quantum
A qubit's amplitude $\alpha$ is a complex number. Its probability is $|\alpha|^2$ — the square of its distance from the origin on this plane. Understanding the geometry of the complex plane is the same as understanding where quantum amplitudes live. Once you can picture a complex number as a point in 2D space, everything else in quantum mathematics becomes spatial rather than symbolic.
Section 2

Think of an address in a city on a perfect grid.

Imagine a perfectly rectangular city. Every block is numbered: East/West streets carry the number $a$, North/South streets carry the number $b$. To reach any intersection, you need exactly two numbers: go $a$ blocks East, then $b$ blocks North. Two numbers, two directions, one location.

That's the complex plane. The East/West axis is the real axis — it carries the part $a$. The North/South axis is the imaginary axis — it carries the part $b$. The complex number $z = a + bi$ is the intersection at address $(a, b)$.

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The city grid analogy
$z = 3 + 4i$ means: go 3 blocks East, 4 blocks North. That intersection is a single, unambiguous point. You can describe it as "$3 + 4i$" (the algebraic address) or as the point $(3, 4)$ on the grid — same thing, two notations. Your distance from city hall (the origin) is the length of the direct diagonal path: $\sqrt{3^2 + 4^2} = \sqrt{25} = 5$. That diagonal distance is the modulus.

Notice what this analogy reveals: knowing $a = 3$ and $b = 4$ tells you the address. But the diagonal distance from the origin — the modulus — tells you something different: how far away the point is, regardless of direction. Those two pieces of information together (address and distance) fully characterise any point on the plane.

Section 3

The complex plane: two axes, one point per number.

The complex plane (also called the Argand plane) is a standard 2D coordinate system with a specific assignment:

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The axis assignment
Horizontal axis = the real axis. Points on this axis have $b = 0$: they are ordinary real numbers like $-2$, $0$, $3.14$.

Vertical axis = the imaginary axis. Points on this axis have $a = 0$: they are pure imaginary numbers like $2i$, $-i$.

Every other point has both $a \neq 0$ and $b \neq 0$: these are genuinely complex numbers like $3 + 4i$, $-1 + 2i$.

For any complex number $z = a + bi$, the symbols are defined precisely as follows:

⚡ Instinct Check Real and imaginary parts Advisory — won't block you
For $z = -5 + 3i$, what is $\text{Im}(z)$?
Section 4

The modulus is the Pythagorean distance. The argument is the angle.

Two quantities fully capture everything about a point's position on the complex plane — one for how far, one for which direction:

The Modulus $|z|$

The modulus of $z = a + bi$ is its distance from the origin $(0,0)$. By the Pythagorean theorem applied to the right triangle formed by $a$ (horizontal), $b$ (vertical), and the diagonal $|z|$:

$$|z| = \sqrt{a^2 + b^2}$$

where $a = \text{Re}(z)$ and $b = \text{Im}(z)$. Every step is explicit: $a$ is the horizontal leg, $b$ is the vertical leg, and $\sqrt{a^2 + b^2}$ is the hypotenuse — the straight-line distance from the origin to the point.

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Why the modulus matters in quantum
A qubit's amplitude $\alpha$ is complex. The probability of measuring outcome $|0\rangle$ is $|\alpha|^2$ — the modulus squared. Changing the phase (rotating $\alpha$ around the origin) doesn't change the probability; only changing the modulus does. This is why the complex plane is the right picture: modulus and phase are geometrically independent.

The Argument $\theta$

The argument of $z$ (written $\arg(z)$ or $\theta$) is the angle the line from the origin to $z$ makes with the positive real axis. Measured counter-clockwise in radians (or degrees):

$$\theta = \arg(z) = \arctan\!\left(\frac{b}{a}\right)$$

You'll handle the argument in full detail in M06 (Polar Form). For now, it's enough to see it in the simulator below — drag the point and watch $\theta$ change as the arrow rotates.

⚔️ Prediction Battle Compute before you confirm

Let $z = 3 + 4i$. Before dragging anything — predict $|z|$ in your head. Use $|z| = \sqrt{a^2 + b^2}$ with $a = 3$ and $b = 4$.

✓ Correct — and here's the full derivation:

Given $z = 3 + 4i$, we identify $a = \text{Re}(z) = 3$ and $b = \text{Im}(z) = 4$.

Apply the modulus formula:
$|z| = \sqrt{a^2 + b^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5$

The point $(3, 4)$ is exactly 5 units from the origin. This is a 3-4-5 right triangle — one of the most famous Pythagorean triples. Place $z = 3 + 4i$ in the simulator below and confirm the readout shows $|z| = 5.00$.
Exploration goal
Drag the cyan dot around the complex plane and watch how $a$, $b$, $z$, $|z|$, and $\theta$ update live. First: find $z = 3 + 4i$ and verify $|z| = 5$. Then: find a point where $|z| = 1$ (the unit circle). Notice that many different values of $\theta$ give $|z| = 1$ — that's the circle of phases from M03.
🔬 Explorer Complex plane — drag the point
Drag the cyan dot — or tap anywhere
Blue = real projection ($a$)
Violet = imaginary projection ($b$)
Cyan arrow = $z$
Amber arc = $\theta$
Re(z) = a3.00
Im(z) = b4.00
z = a + bi3.00 + 4.00i
|z| = √(a²+b²)5.00
θ = arg(z)53.1°
⚡ Instinct Check What stays the same on a circle? Advisory — won't block you
Two complex numbers: $z_1 = 1 + 0i$ and $z_2 = 0 + i$. They look very different. What do they have in common?
Quick Check 4 questions — the plane, modulus, and geometry
Lesson Summary

What the complex plane gives you — in three precise statements

  • 📍
    $z = a + bi$ is a 2D point at $(a, b)$
    The real part $a = \text{Re}(z)$ gives the horizontal coordinate. The imaginary part $b = \text{Im}(z)$ gives the vertical coordinate. Every complex number has a unique location on the plane — no two numbers share the same point.
  • 📏
    The modulus $|z| = \sqrt{a^2 + b^2}$ is Pythagorean distance
    The distance from the origin to the point $(a, b)$ is exactly $\sqrt{a^2 + b^2}$ — the Pythagorean theorem applied to the right triangle with legs $a$ and $b$. In quantum mechanics, $|z|^2$ is what probabilities are built from.
  • 🔄
    The argument $\theta$ is the angle — and it's continuous
    You can rotate the point around the origin (keeping $|z|$ fixed) and $\theta$ changes continuously through all angles from $0°$ to $360°$. This is the full circle of phases that M03 showed real numbers can't provide. The complex plane is what makes arbitrary phase possible.
How clearly do you see the complex plane as a geometric object?

You can now place any complex number on a plane.
You can measure its distance from the origin.
But there's another way to describe a point —
by its distance and angle alone, no coordinates needed.

→ Next: Polar Form — M06
Sources & Further Reading
← Previous
The Imaginary Unit
M04 — What $i$ actually is